Optimal. Leaf size=173 \[ -\frac{d^4 (256 d+165 e x) \sqrt{d^2-e^2 x^2}}{240 e^5}-\frac{8 d^3 x^2 \sqrt{d^2-e^2 x^2}}{15 e^3}-\frac{11 d^2 x^3 \sqrt{d^2-e^2 x^2}}{24 e^2}-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}+\frac{11 d^6 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{16 e^5} \]
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Rubi [A] time = 0.226878, antiderivative size = 173, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {1809, 833, 780, 217, 203} \[ -\frac{d^4 (256 d+165 e x) \sqrt{d^2-e^2 x^2}}{240 e^5}-\frac{8 d^3 x^2 \sqrt{d^2-e^2 x^2}}{15 e^3}-\frac{11 d^2 x^3 \sqrt{d^2-e^2 x^2}}{24 e^2}-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}+\frac{11 d^6 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{16 e^5} \]
Antiderivative was successfully verified.
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Rule 1809
Rule 833
Rule 780
Rule 217
Rule 203
Rubi steps
\begin{align*} \int \frac{x^4 (d+e x)^2}{\sqrt{d^2-e^2 x^2}} \, dx &=-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}-\frac{\int \frac{x^4 \left (-11 d^2 e^2-12 d e^3 x\right )}{\sqrt{d^2-e^2 x^2}} \, dx}{6 e^2}\\ &=-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}+\frac{\int \frac{x^3 \left (48 d^3 e^3+55 d^2 e^4 x\right )}{\sqrt{d^2-e^2 x^2}} \, dx}{30 e^4}\\ &=-\frac{11 d^2 x^3 \sqrt{d^2-e^2 x^2}}{24 e^2}-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}-\frac{\int \frac{x^2 \left (-165 d^4 e^4-192 d^3 e^5 x\right )}{\sqrt{d^2-e^2 x^2}} \, dx}{120 e^6}\\ &=-\frac{8 d^3 x^2 \sqrt{d^2-e^2 x^2}}{15 e^3}-\frac{11 d^2 x^3 \sqrt{d^2-e^2 x^2}}{24 e^2}-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}+\frac{\int \frac{x \left (384 d^5 e^5+495 d^4 e^6 x\right )}{\sqrt{d^2-e^2 x^2}} \, dx}{360 e^8}\\ &=-\frac{8 d^3 x^2 \sqrt{d^2-e^2 x^2}}{15 e^3}-\frac{11 d^2 x^3 \sqrt{d^2-e^2 x^2}}{24 e^2}-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}-\frac{d^4 (256 d+165 e x) \sqrt{d^2-e^2 x^2}}{240 e^5}+\frac{\left (11 d^6\right ) \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx}{16 e^4}\\ &=-\frac{8 d^3 x^2 \sqrt{d^2-e^2 x^2}}{15 e^3}-\frac{11 d^2 x^3 \sqrt{d^2-e^2 x^2}}{24 e^2}-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}-\frac{d^4 (256 d+165 e x) \sqrt{d^2-e^2 x^2}}{240 e^5}+\frac{\left (11 d^6\right ) \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )}{16 e^4}\\ &=-\frac{8 d^3 x^2 \sqrt{d^2-e^2 x^2}}{15 e^3}-\frac{11 d^2 x^3 \sqrt{d^2-e^2 x^2}}{24 e^2}-\frac{2 d x^4 \sqrt{d^2-e^2 x^2}}{5 e}-\frac{1}{6} x^5 \sqrt{d^2-e^2 x^2}-\frac{d^4 (256 d+165 e x) \sqrt{d^2-e^2 x^2}}{240 e^5}+\frac{11 d^6 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{16 e^5}\\ \end{align*}
Mathematica [A] time = 0.111076, size = 103, normalized size = 0.6 \[ \frac{165 d^6 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\sqrt{d^2-e^2 x^2} \left (128 d^3 e^2 x^2+110 d^2 e^3 x^3+165 d^4 e x+256 d^5+96 d e^4 x^4+40 e^5 x^5\right )}{240 e^5} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.07, size = 174, normalized size = 1. \begin{align*} -{\frac{{x}^{5}}{6}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{11\,{d}^{2}{x}^{3}}{24\,{e}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{11\,{d}^{4}x}{16\,{e}^{4}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}+{\frac{11\,{d}^{6}}{16\,{e}^{4}}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}-{\frac{2\,d{x}^{4}}{5\,e}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{8\,{d}^{3}{x}^{2}}{15\,{e}^{3}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{16\,{d}^{5}}{15\,{e}^{5}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.46733, size = 224, normalized size = 1.29 \begin{align*} -\frac{1}{6} \, \sqrt{-e^{2} x^{2} + d^{2}} x^{5} - \frac{2 \, \sqrt{-e^{2} x^{2} + d^{2}} d x^{4}}{5 \, e} - \frac{11 \, \sqrt{-e^{2} x^{2} + d^{2}} d^{2} x^{3}}{24 \, e^{2}} - \frac{8 \, \sqrt{-e^{2} x^{2} + d^{2}} d^{3} x^{2}}{15 \, e^{3}} + \frac{11 \, d^{6} \arcsin \left (\frac{e^{2} x}{\sqrt{d^{2} e^{2}}}\right )}{16 \, \sqrt{e^{2}} e^{4}} - \frac{11 \, \sqrt{-e^{2} x^{2} + d^{2}} d^{4} x}{16 \, e^{4}} - \frac{16 \, \sqrt{-e^{2} x^{2} + d^{2}} d^{5}}{15 \, e^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.82931, size = 236, normalized size = 1.36 \begin{align*} -\frac{330 \, d^{6} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) +{\left (40 \, e^{5} x^{5} + 96 \, d e^{4} x^{4} + 110 \, d^{2} e^{3} x^{3} + 128 \, d^{3} e^{2} x^{2} + 165 \, d^{4} e x + 256 \, d^{5}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{240 \, e^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 13.5183, size = 561, normalized size = 3.24 \begin{align*} d^{2} \left (\begin{cases} - \frac{3 i d^{4} \operatorname{acosh}{\left (\frac{e x}{d} \right )}}{8 e^{5}} + \frac{3 i d^{3} x}{8 e^{4} \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} - \frac{i d x^{3}}{8 e^{2} \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} - \frac{i x^{5}}{4 d \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} & \text{for}\: \frac{\left |{e^{2} x^{2}}\right |}{\left |{d^{2}}\right |} > 1 \\\frac{3 d^{4} \operatorname{asin}{\left (\frac{e x}{d} \right )}}{8 e^{5}} - \frac{3 d^{3} x}{8 e^{4} \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} + \frac{d x^{3}}{8 e^{2} \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} + \frac{x^{5}}{4 d \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} & \text{otherwise} \end{cases}\right ) + 2 d e \left (\begin{cases} - \frac{8 d^{4} \sqrt{d^{2} - e^{2} x^{2}}}{15 e^{6}} - \frac{4 d^{2} x^{2} \sqrt{d^{2} - e^{2} x^{2}}}{15 e^{4}} - \frac{x^{4} \sqrt{d^{2} - e^{2} x^{2}}}{5 e^{2}} & \text{for}\: e \neq 0 \\\frac{x^{6}}{6 \sqrt{d^{2}}} & \text{otherwise} \end{cases}\right ) + e^{2} \left (\begin{cases} - \frac{5 i d^{6} \operatorname{acosh}{\left (\frac{e x}{d} \right )}}{16 e^{7}} + \frac{5 i d^{5} x}{16 e^{6} \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} - \frac{5 i d^{3} x^{3}}{48 e^{4} \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} - \frac{i d x^{5}}{24 e^{2} \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} - \frac{i x^{7}}{6 d \sqrt{-1 + \frac{e^{2} x^{2}}{d^{2}}}} & \text{for}\: \frac{\left |{e^{2} x^{2}}\right |}{\left |{d^{2}}\right |} > 1 \\\frac{5 d^{6} \operatorname{asin}{\left (\frac{e x}{d} \right )}}{16 e^{7}} - \frac{5 d^{5} x}{16 e^{6} \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} + \frac{5 d^{3} x^{3}}{48 e^{4} \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} + \frac{d x^{5}}{24 e^{2} \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} + \frac{x^{7}}{6 d \sqrt{1 - \frac{e^{2} x^{2}}{d^{2}}}} & \text{otherwise} \end{cases}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.18962, size = 113, normalized size = 0.65 \begin{align*} \frac{11}{16} \, d^{6} \arcsin \left (\frac{x e}{d}\right ) e^{\left (-5\right )} \mathrm{sgn}\left (d\right ) - \frac{1}{240} \,{\left (256 \, d^{5} e^{\left (-5\right )} +{\left (165 \, d^{4} e^{\left (-4\right )} + 2 \,{\left (64 \, d^{3} e^{\left (-3\right )} +{\left (55 \, d^{2} e^{\left (-2\right )} + 4 \,{\left (12 \, d e^{\left (-1\right )} + 5 \, x\right )} x\right )} x\right )} x\right )} x\right )} \sqrt{-x^{2} e^{2} + d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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